tag:blogger.com,1999:blog-2433841880619171855.post1997448340425918117..comments2024-03-27T21:09:44.320+00:00Comments on Pat'sBlog: Powers of three.... Continue the PatternUnknownnoreply@blogger.comBlogger1125tag:blogger.com,1999:blog-2433841880619171855.post-81259137881527034522009-09-25T06:51:45.359+01:002009-09-25T06:51:45.359+01:00Start at (3^(n div 2) + 1) / 2, add 3^(n div 2) (n...Start at (3^(n div 2) + 1) / 2, add 3^(n div 2) (n even) or 2*3^(n div 2) (n odd) consecutive integers, and you get 3^n.I. J. Kennedyhttps://www.blogger.com/profile/04805435564360543720noreply@blogger.com