tag:blogger.com,1999:blog-2433841880619171855.post830447138064140342..comments2024-03-27T21:09:44.320+00:00Comments on Pat'sBlog: A Problem for AlUnknownnoreply@blogger.comBlogger2125tag:blogger.com,1999:blog-2433841880619171855.post-65800149493086766502009-01-05T07:48:00.000+00:002009-01-05T07:48:00.000+00:00I agree with Sam, It seems that anonymous took an ...I agree with Sam, It seems that anonymous took an amount equal to 1/10 of the remaining amount.Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-2433841880619171855.post-73096873788117763772009-01-05T07:44:00.000+00:002009-01-05T07:44:00.000+00:00If you take 72 from a total of 5832 there will be ...If you take 72 from a total of 5832 there will be 5760 remaining, and 1/9 of this number is 640, so it seems they should have taken 712, which would not be 1/9 of the total. <BR/>Maybe we have interpreted "1/9 of the remainder" differently.Anonymousnoreply@blogger.com