tag:blogger.com,1999:blog-2433841880619171855.post9220872567191802576..comments2020-07-04T10:03:46.679+01:00Comments on Pat'sBlog: Testing Understanding of SlopeUnknownnoreply@blogger.comBlogger2125tag:blogger.com,1999:blog-2433841880619171855.post-33918149622037441342009-04-08T10:33:00.000+01:002009-04-08T10:33:00.000+01:00By inspiring from your statement "The questio...By inspiring from your statement <BR/><BR/>"The questions, shown below, were of the lines y=3/4 x -3 and y=3/4 x - 2"<BR/><BR/>Because I am physicsist, after reading your explanation and looking it's graph representation, I remember to way of Mr.Einstein in getting Planck constant (h) via fitting curve of his Photo Elecric data to the model linear equation Vs = (h/e)f - (h/e)f0 of the Stopping Potential (Vs) graph respect to the frequency of monochomatic light (f). Here e is electron charge, while f0 is the threshold frequency of light used on his photo electric experiment. <BR/><BR/>Appear that Vs = (h/e)f - (h/e)f0 similar to y = mx + C, where m is the slope and C is the common constant in a linear equation.<BR/><BR/>The positive value of h corresponds to to 3/4 number, while the threshold frequency (f0) corresponds to the number behind minus sign of the constant. <BR/><BR/>Both of 3 and 2 values of your constant corresponds to the minimum energy (hf0) needed to elapse every one electron from the surface of chatoda plate. The two different value of the above constant can explain the dependency of stopping potential to the conductor materials used as photo chatoda plate.<BR/><BR/>Thanks for your excelent explanation Mr.Pat.<BR/><BR/>Oh yeah Mr.Pat, at the following link :<BR/><BR/>http://eqworld.ipmnet.ru/forum/viewtopic.php?f=3&t=148 <BR/><BR/>I have been posting the New Pi Exact Formula in sum of two arcsin. If you have alot of spare time please visit to the link. Hopefully my pi exact formula can give rise the future scientific on the world.<BR/><BR/>Special sallom for you from my daughter Denaya Lesa. Now, she focus to prepare her final exam.<BR/><BR/><BR/>Best Regards,<BR/>AFASMT/Rohedi.Rohedihttps://www.blogger.com/profile/18001346866144585275noreply@blogger.comtag:blogger.com,1999:blog-2433841880619171855.post-33175199068752997372009-04-08T10:31:00.000+01:002009-04-08T10:31:00.000+01:00By inspiring from your statement :"The questi...By inspiring from your statement :<BR/>"The questions, shown below, were of the lines y=3/4 x -3 and y=3/4 x - 2"<BR/><BR/>Because I am physicsist, after reading your explanation and looking it's graph representation, I remember to way of Mr.Einstein in getting Planck constant (h) via fitting curve of his Photo Elecric data to the model linear equation Vs = (h/e)f - (h/e)f0 of the Stopping Potential (Vs) graph respect to the frequency of monochomatic light (f). Here e is electron charge, while f0 is the threshold frequency of light used on his photo electric experiment. <BR/><BR/>Appear that Vs = (h/e)f - (h/e)f0 similar to y = mx + C, where m is the slope and C is the common constant in a linear equation.<BR/><BR/>The positive value of h corresponds to to 3/4 number, while the threshold frequency (f0) corresponds to the number behind minus sign of the constant. <BR/><BR/>Both of 3 and 2 values of your constant corresponds to the minimum energy (hf0) needed to elapse every one electron from the surface of chatoda plate. The two different value of the above constant can explain the dependency of stopping potential to the conductor materials used as photo chatoda plate.<BR/><BR/>Thanks for your excelent explanation Mr.Pat.<BR/><BR/>Oh yeah Mr.Pat, at the following link :<BR/><BR/>http://eqworld.ipmnet.ru/forum/viewtopic.php?f=3&t=148 <BR/><BR/>I have been posting the New Pi Exact Formula in sum of two arcsin. If you have alot of spare time please visit to the link. Hopefully my pi exact formula can give rise the future scientific on the world.<BR/><BR/>Special sallom for you from my daughter Denaya Lesa. Now, she focuses to prepare her final exam.<BR/><BR/><BR/>Best Regards,<BR/>AFASMT/Rohedi.Rohedihttps://www.blogger.com/profile/18001346866144585275noreply@blogger.com