Came across a geometry problem with an interesting result which I did not suspect... thought I would share...
In the figure, rectangle ABCD is inscribed with a triangle by selecting points E and F on the segments AB and BC respectively, so that triangles AED, BEF, and CFD all have equal area. Find the ratios of AE:EB and BF:FC. I was surprised, and pleased, hope you are as well.
5 comments:
ok, what's going on here?
I recalculated with some actual numbers to make sure I hadn't goofed.
What's making this happen?
Jonathan
Wow!!!
the answer is golden ratio
how can AED possibly equal to BEF ?
are of triangle are equal ? thats impossible
Tenzin, just like in the textbook, triangles are not (necessarily) drawn to scale. Your job is to find the locations of points E and F that make the equality happen. Try again.
((6^(1/2))-1)/2
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