^{2}+bx+c=0.

I was impressed that a high school age student would come up with the idea of a transformation from a quadratic to a point on the plane. THEN.... a few days ago I came across a post from the Mathematical Gazette, January of 1913, entitled "A Graphic Solution of the Equation x

^{n}-px+q=0, much of which dealt with the idea that the curve 4y=x

^{2}(which the author called the Discriminant Curve) would serve as a graphic solution approach for any quadratic of the form x

^{2}-px+q=0.

Note the use of -p, a step up from what young Anthony had used, making it a slightly more useful approach, and perhaps testifying to the independence of his discovery. The author of the piece, A. Lodge, (with no other information given), did not claim it as original, nor site another use.

So the solutions to the equation x

^{2}-px+q=0 are found by the points where the tangents to 4y=x

^{2}intersect the x-axis.

The article also pointed out, and I admit I had never thought of this, that the solutions to x

^{2}-px+q=0 are the same as the solutions to $x^2-\frac{p}{k}x+\frac{q}{k^2}=0$. It is easy enough to prove, but for the use of a nomograph like the approximations using the graph of 4y=x

^{2}, it allows you to work on a much narrower range of x and y values.

The article also referred to solutions of higher powers of trinomials that could be solved in the same way, but my little mind has not grasped it enough to explain it yet, so I save that for another day...

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